Electronics Engineering  ·  Level 6
Electrical Principles II
Chapter 3: Apply transients in DC Circuits
📚 3 Topics
⚑ What you will be able to do

By the end of this chapter, you will be able to: - accurately determine resistance and resistivity in a DC circuit following IEC standards - correctly apply AC fundamentals by understanding and using the working principles - confidently perform calculations involving passive elements in AC circuits based on specific circuit requirements

Mastering these skills will help you troubleshoot and work safely and effectively with both DC and AC circuits in real-world electrical jobs.

The understanding of transient phenomena in direct current (DC) circuits is essential for professionals across various Kenyan industries. Transient responses occur when a circuit experiences sudden changes, such as switching on or off, and they significantly influence the performance and safety of electrical systems in places like county hospitals, banks, and educational institutions. This chapter explores how voltages and currents evolve over time in resistive-inductive (R-L) and resistive-capacitive (R-C) circuits, providing the necessary theoretical foundation and practical calculation methods. Mastery of these concepts ensures effective management of electrical equipment and prevents damage caused by unexpected transient behaviors.

3.1 Derivation of Growth and Decay Equations in R-L and R-C Circuits

The transient response of electrical circuits containing inductors and capacitors differs fundamentally from that of purely resistive circuits due to energy storage elements. When a DC voltage is applied or removed, the current or voltage does not change instantaneously but follows exponential growth or decay patterns governed by differential equations. Understanding these patterns is crucial for professionals managing complex electrical systems, such as those in county government offices or retail businesses, where inductive motors or capacitive filters are common.

3.1.1 Derivation of Growth Equation in R-L Circuits

The growth equation describes how current increases when an inductive load is connected to a DC supply through a resistor. Upon closing the switch, the inductor initially opposes changes in current due to its stored magnetic energy, causing a gradual rise.

The governing differential equation for the current i(t) in an R-L circuit connected to a DC voltage V is:

V = L (di/dt) + R i

Rearranging:

L (di/dt) = V - R i

Dividing both sides by L:

di/dt = (V/L) - (R/L) i

This is a first-order linear differential equation. Using integrating factor methods, the solution for current growth starting from zero at time t=0 is:

i(t) = (V/R)(1 - e^(-Rt/L))

where:

  • V/R is the final steady-state current,

  • e is the base of natural logarithms,

  • Rt/L is the dimensionless time variable.

The term τ = L/R is called the time constant of the circuit, representing the time for current to reach approximately 63.2% of its final value.

In practical terms, this means that in a hospital's emergency power system, the current through an inductive load such as a motor will not instantly reach its full value but will increase exponentially, affecting the design of protective devices.

3.1.2 Derivation of Decay Equation in R-L Circuits

When the supply voltage is suddenly removed from an R-L circuit, the current does not fall to zero instantly because the inductor releases stored energy. The current decays exponentially according to:

L (di/dt) + R i = 0

Rearranged:

di/dt = -(R/L) i

This homogenous differential equation has the solution:

i(t) = I₀ e^(-Rt/L)

where I₀ is the initial current at the moment the supply is disconnected.

The current decreases to 36.8% of its initial value after one time constant τ = L/R.

3.1.3 Derivation of Growth Equation in R-C Circuits

In an R-C circuit, when a DC voltage is applied, the capacitor charges through the resistor causing the voltage across the capacitor to rise exponentially.

The voltage across the capacitor v_c(t) satisfies:

V = v_c + R i

Since i = C (dv_c/dt), substituting:

V = v_c + R C (dv_c/dt)

Rearranged:

dv_c/dt + (1/RC) v_c = V / (RC)

The solution with zero initial voltage at t=0 is:

v_c(t) = V (1 - e^(-t/RC))

Here, τ = RC is the time constant representing the time for the capacitor voltage to reach 63.2% of the supply voltage.

In a retail business using power factor correction capacitors, understanding this charging behavior helps avoid sudden voltage changes that could damage equipment.

3.1.4 Derivation of Decay Equation in R-C Circuits

When the supply is disconnected, the capacitor discharges through the resistor, and the voltage across it decays exponentially according to:

dv_c/dt + (1/RC) v_c = 0

The solution is:

v_c(t) = V₀ e^(-t/RC)

where V₀ is the initial voltage across the capacitor at the moment of disconnection.

The voltage falls to 36.8% of its initial value after one time constant τ = RC.

3.1.5 Sketching of Growth and Decay Curves in R-L and R-C Circuits

Graphical representation of transient responses aids in visualizing how current or voltage changes over time, reinforcing understanding.

In R-L circuits:

  • The growth curve of current starts at zero and asymptotically approaches the steady-state value V/R.

  • The decay curve starts from initial current I₀ and exponentially decreases toward zero.

In R-C circuits:

  • The voltage growth curve begins at zero and approaches the supply voltage V asymptotically.

  • The voltage decay curve starts at initial voltage V₀ and exponentially decreases toward zero.

The time constant τ defines the characteristic time scale on these curves, with the value at t = τ marking approximately 63.2% of growth or 36.8% of decay.

3.1.6 Calculations Involving Growth and Decay Based on Time Constants

Calculating transient responses requires applying the growth or decay formulas with given circuit parameters.

Example calculation:

Given an R-L circuit with R = 20 Ω, L = 0.1 H, and supply voltage V = 240 V, find the current after 0.005 seconds.

Step 1: Calculate time constant

τ = L / R = 0.1 / 20 = 0.005 seconds

Step 2: Apply growth formula

i(t) = (V / R) (1 - e^(-t / τ))

Substitute values:

i(0.005) = (240 / 20) (1 - e^(-0.005 / 0.005))

Calculate exponent:

-0.005 / 0.005 = -1

Calculate exponential:

e^(-1) ≈ 0.3679

Calculate current:

i(0.005) = 12 (1 - 0.3679) = 12 × 0.6321 = 7.585 A

This calculation is crucial for sizing circuit breakers in county government offices to handle transient currents safely.

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🔒3.2 Application of the Effect of Time Constant in Switching Inductive and Capacitive Loads

The time constant governs the rate at which voltages and currents change during switching, impacting the design and operation of electrical systems in diverse sectors. Understanding these effects helps prevent equipment damage, improve power quality, and enhan…

🔒3.3 Analysis of Passive and Active Filters

In diverse Kenyan workplaces such as hospitals, banks, and county government offices, electrical circuits often require conditioning to ensure signal quality and system stability. Filters play a crucial role in managing unwanted frequencies and noise in electr…

Chapter Summary

This chapter focused on the behavior of transients in direct current circuits, specifically examining the derivation of growth and decay equations for resistor-inductor (R-L) and resistor-capacitor (R-C) circuits. It covered how to sketch the growth and decay curves that represent voltage or current changes over time in these circuits. Calculations based on time constants were explored to quantify the rate at which these transients occur, providing a mathematical understanding of circuit responses. The chapter then discussed the practical application of time constants when switching inductive and capacitive loads, highlighting how these factors influence circuit performance and stability. Finally, the analysis of passive and active filters was introduced, demonstrating how these filters manipulate signal frequencies in electrical systems. Together, these topics build a comprehensive understanding of transient phenomena and their significance in designing and controlling DC circuits.

Self-Assessment

🔒 PDFDownload this self-assessment, with answers

A. Written Assessment

  1. Define the time constant in an R-L circuit and explain its significance. (3 marks)
  2. Sketch the growth curve of current in an R-L circuit and label all relevant parameters. (4 marks)
🔒20 more in this section.

Chapter Examination Questions

🔒 PDFDownload these examination questions, with worked answers

SECTION A (40 Marks) - Answer ALL Questions

  1. A 10 H inductor and a 5 Ω resistor are connected in series to a 100 V DC supply. Calculate the time constant of the circuit. (4 marks)
  2. Sketch the growth curve of current in an R-L circuit and label the time constant on the graph. (4 marks)
🔒18 more in this section.

Chapter Practical Activities

Practical 1: Derive the growth equation for current in an R-L circuit

Electronics Engineering · Level 6
Electrical Principles II
PRACTICAL ASSESSMENT
TIME: 4 HOURS
⬇ PDFCandidate Instructions (Candidate Tool)

Type: Individual

INSTRUCTIONS TO CANDIDATE:
1.  You are required to perform the following task:
i.  Derive and graphically represent the current growth equation for an R-L circuit with R = 10 Ω and L = 0.5 H during switching on.
2.  You have been provided with the following resources for the practical task:
Tools & EquipmentMaterials
Scientific calculatorRheostat 10 Ω
Stopwatch or timerInductor 0.5 H
MultimeterDC power supply 12 V
Connecting wires
Graph paper A4 size
Pen and pencil set
R-L circuit theoretical notes
⬇ PDFResources Required (Cutting List)
S/NItemQuantity
1R-L circuit theoretical notes1 set per Candidate
2Scientific calculator1 Pc per Candidate
3Graph paper A4 size2 sheets per Candidate
4Pen and pencil set1 set per Candidate
5Rheostat 10 Ω1 Pc per Candidate
6Inductor 0.5 H1 Pc per Candidate
7DC power supply 12 V1 Pc per Candidate
8Connecting wires3 m per Candidate
9Stopwatch or timer1 Pc per Candidate
10Multimeter1 Pc per Candidate
11PPE (Safety boots, gloves, goggles)1 set per Candidate
⬇ PDFAssessor Guide
Items to be EvaluatedMarks AvailableMarks ObtainedComments
TASK 1: Safety and preparation
Wore safety clothing including safety boots, gloves, and goggles
(Award 2 marks for full PPE, 0 if incomplete)
2
Checked and listed all tools and materials before starting
(Award 2 marks for complete and accurate list)
2
Set up R-L circuit correctly with given components
(Award 3 marks if circuit is correctly connected)
3
Used multimeter and timer appropriately for measurements
(Award 3 marks for correct use of instruments)
3
Sub-Total10
TASK 2: Derivation and calculations
Correctly wrote the differential equation for the growth of current in R-L circuit
(Award 5 marks for accurate equation derivation)
5
Performed integration steps correctly to derive growth equation
(Award 7 marks for correct integration and boundary conditions)
7
Substituted correct values for R and L and simplified the expression
(Award 3 marks for correct substitution and simplification)
3
Calculated time constant τ = L/R correctly
(Award 3 marks for accurate calculation of τ)
3
Sub-Total18
TASK 3: Graphical representation and conclusion
Plotted current growth curve against time accurately on graph paper
(Award 5 marks for neat and correct plotting with labelled axes)
5
Correctly indicated initial current and steady state current on graph
(Award 3 marks for correct annotation on graph)
3
Explained physical meaning of the growth equation and time constant
(Award 4 marks for clear explanation)
4
Sub-Total12
PRODUCT CHECKLIST
Derived growth equation matches theoretical formula: i(t) = (V/R)(1 - e^(-Rt/L))
(Award 6 marks for correct final equation)
6
Time constant τ calculated as 0.05 seconds (L=0.5 H, R=10 Ω)
(Award 4 marks for accurate τ value)
4
Graph shows exponential growth from 0 A to 1.2 A over time with correct shape
(Award 5 marks for graph accuracy and neatness)
5
Annotations and labels on graph are clear and correct
(Award 3 marks for proper labeling)
3
Sub-Total18
GRAND TOTAL58
ASSESSMENT OUTCOME:   ☐ Competent    ☐ Not Yet Competent (competent if at least 50%)

Practical 2: Derive the Voltage Decay Equation for an R-C Circuit

Electronics Engineering · Level 6
Electrical Principles II
PRACTICAL ASSESSMENT
TIME: 4 HOURS
⬇ PDFCandidate Instructions (Candidate Tool)

Type: Individual

INSTRUCTIONS TO CANDIDATE:
1.  You are required to perform the following task:
i.  Derive and verify the voltage decay equation across a 100 μF capacitor in an R-C circuit with a 10 kΩ resistor during switching off.
2.  You have been provided with the following resources for the practical task:
Tools & EquipmentMaterials
Digital MultimeterResistor 10 kΩ, 1/4 Watt
Stopwatch or TimerCapacitor 100 μF, 50 V Electrolytic
CalculatorDC Power Supply 12 V
Connecting wires with alligator clips
Breadboard or Circuit Board
Safety gloves and Goggles
Graph paper A4 size
⬇ PDFResources Required (Cutting List)
S/NItemQuantity
1Resistor 10 kΩ, 1/4 Watt1 Pc per Candidate
2Capacitor 100 μF, 50 V Electrolytic1 Pc per Candidate
3DC Power Supply 12 V1 Pc per Candidate
4Digital Multimeter1 Pc per Candidate
5Stopwatch or Timer1 Pc per Candidate
6Connecting wires with alligator clips5 Meters per Candidate
7Breadboard or Circuit Board1 Pc per Candidate
8Safety gloves and Goggles1 Set per Candidate
9Graph paper A4 size2 Sheets per Candidate
10Calculator1 Pc per Candidate
⬇ PDFAssessor Guide
Items to be EvaluatedMarks AvailableMarks ObtainedComments
TASK 1: Safety and Preparation
Wore safety gloves and goggles before starting the experiment
(Award 2 marks for correct PPE use, 0 if not)
2
Assembled the R-C circuit correctly on the breadboard
(Award 3 marks for correct component placement and wiring)
3
Checked all connections for firmness and correct polarity
(Award 2 marks for secure and correct connections)
2
Set the DC power supply to 12 V and switched on safely
(Award 2 marks for correct voltage setting and safe operation)
2
Sub-Total9
TASK 2: Data Collection and Derivation
Measured the initial voltage across the capacitor before switching off
(Award 2 marks for accurate initial voltage measurement)
2
Recorded voltage decay readings at regular intervals using the multimeter and stopwatch
(Award 4 marks for systematic and accurate data recording)
4
Plotted voltage decay versus time graph neatly on graph paper
(Award 5 marks for neat and accurate graph plotting)
5
Derived the mathematical decay equation for voltage across the capacitor using data and theory
(Award 10 marks for correct derivation and explanation)
10
Explained the physical meaning of the time constant in the R-C circuit
(Award 5 marks for clear explanation related to circuit behavior)
5
Sub-Total26
TASK 3: Cleanup and Housekeeping
Switched off the power supply and safely disassembled the circuit
(Award 2 marks for safe disassembly)
2
Returned all tools and materials to their proper places
(Award 2 marks for proper housekeeping)
2
Cleaned the workspace leaving it tidy
(Award 1 mark for good housekeeping)
1
Sub-Total5
PRODUCT CHECKLIST
Voltage decay graph matches expected exponential decay with time constant τ = RC (τ = 1,000 ms)
(Award 10 marks for correct graph shape and time constant verification)
10
Mathematical decay equation correctly derived: V(t) = V₀ e^(-t/RC)
(Award 10 marks for correct and complete derivation)
10
Data tables are complete, accurate and well-organized
(Award 5 marks for clear and accurate data presentation)
5
Sub-Total25
GRAND TOTAL65
ASSESSMENT OUTCOME:   ☐ Competent    ☐ Not Yet Competent (competent if at least 50%)
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🔒Sketch growth and decay curves for an R-L circuitPractical 3
🔒Sketch voltage growth and decay curves for an R-C circuitPractical 4
🔒Calculate time constant and transient current in an R-L circuitPractical 5
🔒Calculate Time Constant and Transient Voltages in an R-C CircuitPractical 6
🔒Demonstrate Switching Effect on an Inductive LoadPractical 7
🔒Demonstrate switching effect on a capacitive load in a DC circuitPractical 8
🔒Construct and test a passive RC low-pass filter circuit 1000Hz cutoff frequencyPractical 9
🔒Construct and Analyze a 1000Hz Active Low-Pass Filter CircuitPractical 10
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Am I competent?

At the start of this chapter we promised you would be able to:

  • accurately determine resistance and resistivity in a DC circuit following IEC standards
  • correctly apply AC fundamentals by understanding and using the working principles
  • confidently perform calculations involving passive elements in AC circuits based on specific circuit requirements

Tick each one you can genuinely do.

So, are you there yet?

You're competent when you can confidently do 50% or more of what this chapter promised.

Sign in to record how you're doing.