Mechatronics Technology  ·  Level 6
Engineering Mathematics I
Chapter 2: Apply trigonometric and hyperbolic functions
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Engineering mathematics plays a critical role in mechatronics technology, especially in analyzing systems involving angles and hyperbolic functions. These mathematical tools are essential for understanding sensor data, actuator positioning, and robotic arm movements in Kenyan industries such as manufacturing, automation, and precision agriculture. Mastery of trigonometric and hyperbolic functions enables professionals to model and solve practical problems involving angular measurements and hyperbolic relationships in control systems and signal processing.

2.1 Angles and Hyperbolic

Angles and hyperbolic functions frequently arise in mechatronics when dealing with rotational components, oscillations, and nonlinear system behaviors. Understanding how to calculate and apply these functions for different angle types, acute, obtuse, reflex, and right angles, is fundamental for system design and analysis. Hyperbolic functions, which resemble trigonometric functions but relate to hyperbolas instead of circles, are also crucial in describing certain dynamic responses and electrical properties.

2.1.1 Acute Angles

Acute angles are angles less than 90 degrees. In mechatronics, acute angles are common in joint articulations, sensor alignments, and component mounting. The primary trigonometric functions for acute angles, sine, cosine, and tangent, are used to resolve forces, calculate displacements, and analyze signal phases.

The basic relations are:

$$\sin \theta = \frac{\text{Opposite side}}{\text{Hypotenuse}}$$$$\cos \theta = \frac{\text{Adjacent side}}{\text{Hypotenuse}}$$$$\tan \theta = \frac{\text{Opposite side}}{\text{Adjacent side}}$$

Worked Examples

Example 1: A robotic arm pivots at an acute angle of 30° to the horizontal. If the arm length is 2 m, find the vertical height reached by the arm tip.

Given:
\(\theta = 30^\circ\), length \(L = 2\,m\)

$$\text{Height} = L \times \sin \theta$$$$= 2 \times \sin 30^\circ$$$$= 2 \times 0.5$$$$= 1\,m$$

Answer: 1 m

Example 2: A sensor is mounted at an acute angle of 45° to detect displacement along the horizontal axis. If the sensor measures a displacement of 1.5 m along its axis, find the horizontal component of this displacement.

Given:
\(\theta = 45^\circ\), displacement \(d = 1.5\,m\)

$$\text{Horizontal component} = d \times \cos \theta$$$$= 1.5 \times \cos 45^\circ$$$$= 1.5 \times 0.707$$$$= 1.06\,m$$

Answer: 1.06 m

Example 3: A conveyor belt is inclined at an acute angle of 60°. Find the length of the belt needed to raise a package vertically by 3 m.

Given:
\(\theta = 60^\circ\), vertical height \(h = 3\,m\)

$$L = \frac{h}{\sin \theta}$$$$= \frac{3}{\sin 60^\circ}$$$$= \frac{3}{0.866}$$$$= 3.46\,m$$

Answer: 3.46 m

Example 4: In a control system, an actuator arm forms an acute angle of 20° with the horizontal. The horizontal displacement needed is 0.8 m. Find the required actuator arm length.

Given:
\(\theta = 20^\circ\), horizontal displacement \(x = 0.8\,m\)

$$L = \frac{x}{\cos \theta}$$$$= \frac{0.8}{\cos 20^\circ}$$$$= \frac{0.8}{0.940}$$$$= 0.85\,m$$

Answer: 0.85 m

Example 5: A sensor detects a force vector at an acute angle of 15° to the horizontal. The measured force magnitude is 50 N. Calculate the vertical component of the force.

Given:
\(\theta = 15^\circ\), force \(F = 50\,N\)

$$F_y = F \times \sin \theta$$$$= 50 \times \sin 15^\circ$$$$= 50 \times 0.259$$$$= 12.95\,N$$

Answer: 12.95 N

2.1.2 Obtuse Angles

Obtuse angles are angles greater than 90 degrees but less than 180 degrees. In mechatronics, obtuse angles often occur in joint configurations and sensor alignments where components rotate beyond a right angle. Trigonometric function values for obtuse angles can be derived using reference angles and sign rules.

The sine function remains positive in the second quadrant (90° to 180°), while cosine and tangent become negative:

$$\sin \theta = \sin (180^\circ - \theta)$$$$\cos \theta = -\cos (180^\circ - \theta)$$$$\tan \theta = -\tan (180^\circ - \theta)$$

Worked Examples

Example 1: A robotic joint forms an angle of 120° with the reference axis. Calculate \(\sin 120^\circ\), \(\cos 120^\circ\), and \(\tan 120^\circ\).

Given:
\(\theta = 120^\circ\)
Reference angle \(= 180^\circ - 120^\circ = 60^\circ\)

$$\sin 120^\circ = \sin 60^\circ = 0.866$$$$\cos 120^\circ = -\cos 60^\circ = -0.5$$$$\tan 120^\circ = -\tan 60^\circ = -1.732$$

Answer: \(\sin 120^\circ = 0.866\), \(\cos 120^\circ = -0.5\), \(\tan 120^\circ = -1.732\)

Example 2: An actuator arm rotates to 135°. Find the horizontal and vertical components of a 10 N force applied along the arm.

Given:
\(\theta = 135^\circ\), \(F = 10\,N\)
Reference angle \(= 45^\circ\)

$$F_x = F \times \cos 135^\circ = 10 \times (-\cos 45^\circ) = 10 \times (-0.707) = -7.07\,N$$$$F_y = F \times \sin 135^\circ = 10 \times \sin 45^\circ = 10 \times 0.707 = 7.07\,N$$

Answer: \(F_x = -7.07\,N\), \(F_y = 7.07\,N\)

Example 3: A sensor is oriented at 150° and measures a displacement of 5 m along its axis. Find the vertical and horizontal components.

Given:
\(\theta = 150^\circ\), \(d = 5\,m\)
Reference angle \(= 30^\circ\)

$$d_x = d \times \cos 150^\circ = 5 \times (-\cos 30^\circ) = 5 \times (-0.866) = -4.33\,m$$$$d_y = d \times \sin 150^\circ = 5 \times \sin 30^\circ = 5 \times 0.5 = 2.5\,m$$

Answer: \(d_x = -4.33\,m\), \(d_y = 2.5\,m\)

Example 4: A robotic arm extends at 110° with a length of 3 m. Calculate the vertical height reached.

Given:
\(\theta = 110^\circ\), \(L = 3\,m\)
Reference angle \(= 70^\circ\)

$$h = L \times \sin 110^\circ = 3 \times \sin 70^\circ = 3 \times 0.940 = 2.82\,m$$

Answer: 2.82 m

Example 5: An electrical signal phase shift is 120°. Calculate the cosine of this angle to determine the real part of the signal.

Given:
\(\theta = 120^\circ\)

$$\cos 120^\circ = -\cos 60^\circ = -0.5$$

Answer: -0.5

2.1.3 Reflex Angles

Reflex angles are angles greater than 180 degrees but less than 360 degrees. These angles appear in mechatronics when dealing with full rotations, gear positions, or angular displacements in continuous rotation systems. Calculations use reference angles and quadrant sign rules to find trigonometric values.

In the third quadrant (180° to 270°), sine is negative, cosine is negative, tangent is positive. In the fourth quadrant (270° to 360°), sine is negative, cosine is positive, tangent is negative.

Worked Examples

Example 1: Find \(\sin 210^\circ\), \(\cos 210^\circ\), and \(\tan 210^\circ\).

Given:
\(\theta = 210^\circ\)
Reference angle \(= 210^\circ - 180^\circ = 30^\circ\)

$$\sin 210^\circ = -\sin 30^\circ = -0.5$$$$\cos 210^\circ = -\cos 30^\circ = -0.866$$$$\tan 210^\circ = \tan 30^\circ = 0.577$$

Answer: \(\sin 210^\circ = -0.5\), \(\cos 210^\circ = -0.866\), \(\tan 210^\circ = 0.577\)

Example 2: A rotating sensor arm moves to 300°. Calculate the sine, cosine, and tangent values.

Given:
\(\theta = 300^\circ\)
Reference angle \(= 360^\circ - 300^\circ = 60^\circ\)

$$\sin 300^\circ = -\sin 60^\circ = -0.866$$$$\cos 300^\circ = \cos 60^\circ = 0.5$$$$\tan 300^\circ = -\tan 60^\circ = -1.732$$

Answer: \(\sin 300^\circ = -0.866\), \(\cos 300^\circ = 0.5\), \(\tan 300^\circ = -1.732\)

Example 3: Calculate the vertical height of a robotic arm of length 4 m positioned at 225°.

Given:
\(\theta = 225^\circ\), \(L = 4\,m\)
Reference angle \(= 225^\circ - 180^\circ = 45^\circ\)

$$h = L \times \sin 225^\circ = 4 \times (-\sin 45^\circ) = 4 \times (-0.707) = -2.83\,m$$

Answer: -2.83 m

Example 4: A motor shaft rotates through a reflex angle of 270°. Find the cosine and sine values.

Given:
\(\theta = 270^\circ\)

$$\sin 270^\circ = -1$$$$\cos 270^\circ = 0$$

Answer: \(\sin 270^\circ = -1\), \(\cos 270^\circ = 0\)

Example 5: A signal phase is 315°. Calculate the tangent value.

Given:
\(\theta = 315^\circ\)
Reference angle \(= 360^\circ - 315^\circ = 45^\circ\)

$$\tan 315^\circ = -\tan 45^\circ = -1$$

Answer: -1

2.1.4 Right Angles

Right angles measure exactly 90 degrees and are fundamental in mechatronics for orthogonal positioning, sensor calibration, and coordinate system definitions. The trigonometric values of right angles are standard and often used as reference points.

The key values are:

$$\sin 90^\circ = 1$$$$\cos 90^\circ = 0$$$$\tan 90^\circ = \text{undefined}$$

Worked Examples

Example 1: Calculate the vertical height of a robotic arm of length 5 m positioned at 90°.

Given:
\(\theta = 90^\circ\), \(L = 5\,m\)

$$h = L \times \sin 90^\circ = 5 \times 1 = 5\,m$$

Answer: 5 m

Example 2: Find the horizontal component of a 7 m arm at 90°.

Given:
\(\theta = 90^\circ\), \(L = 7\,m\)

$$x = L \times \cos 90^\circ = 7 \times 0 = 0\,m$$

Answer: 0 m

Example 3: A force of 20 N acts at 90°. Calculate the tangent of the angle and interpret.

Given:
\(\theta = 90^\circ\)

$$\tan 90^\circ = \text{undefined}$$

The tangent is undefined because the adjacent side is zero, indicating a vertical force direction which cannot be expressed as a ratio of sides.

Answer: Undefined

Example 4: A sensor detects displacement along an arm at 90°, with length 10 m. Find the displacement components.

Given:
\(\theta = 90^\circ\), \(d = 10\,m\)

$$d_x = d \times \cos 90^\circ = 10 \times 0 = 0\,m$$$$d_y = d \times \sin 90^\circ = 10 \times 1 = 10\,m$$

Answer: \(d_x = 0\,m\), \(d_y = 10\,m\)

Example 5: Calculate the sine, cosine, and tangent of 0° and 90° for comparison.

Given:
\(\theta = 0^\circ\) and \(\theta = 90^\circ\)

At 0°:$$\sin 0^\circ = 0$$$$\cos 0^\circ = 1$$$$\tan 0^\circ = 0$$

At 90°:$$\sin 90^\circ = 1$$$$\cos 90^\circ = 0$$$$\tan 90^\circ = \text{undefined}$$

Answer: Values as above.

Practice Questions

  1. A robotic arm of length 2.5 m is positioned at an acute angle of 40°. Calculate the vertical height reached by the arm. (3 marks)
  2. An actuator rotates to 130°, applying a force of 15 N along its length. Find the horizontal and vertical components of the force. (4 marks)
  3. Calculate \(\sin 210^\circ\), \(\cos 210^\circ\), and \(\tan 210^\circ\). (3 marks)
  4. A robotic arm of length 3 m extends at 225°. Find the vertical height reached and interpret the sign. (4 marks)
  5. Calculate the horizontal and vertical displacement components of a sensor reading 8 m at 300°. (4 marks)
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🔒2.2 Triangles

An isosceles triangle has two sides of equal length and two equal angles opposite those sides. This symmetry simplifies many calculations in mechatronic framework design, especially when balancing loads or aligning sensors on symmetrical mounts. The key formul…

🔒2.3 Trigonometric ratios

Trigonometric ratios are fundamental in Mechatronics Technology for analyzing forces, motion, and angles in mechanical and electrical systems. Kenyan mechatronics engineers use these ratios to design robotic arms, sensor alignments, and control mechanisms with…

🔒2.4 Trigonometric Identities

In Mechatronics Technology, proficiency with trigonometric identities is essential for analyzing rotational motion, sensor signals, and actuator positioning. These identities simplify complex expressions and enable solving equations in control systems and robo…

🔒2.5 Trigonometric Equations

Solving trigonometric equations is vital in mechatronics for determining angles of rotation, phase shifts in signals, and timing in control systems. These equations often involve one or more trigonometric functions and require algebraic manipulation and use of…

🔒2.6 Hyperbolic functions

Hyperbolic functions are fundamental in mechatronics technology for modelling nonlinear systems such as actuator response curves, signal processing, and control system stability analysis. In Kenya, mechatronics engineers use hyperbolic functions to analyse rob…

Chapter Summary

This chapter introduced the different types of angles including acute, obtuse, reflex, and right angles, establishing a foundation for understanding their properties and applications. It then explored various triangles such as isosceles, equilateral, right angled, and scalene, highlighting their side and angle relationships. The chapter detailed the six primary trigonometric ratios: sine, cosine, tangent, cosecant, secant, and cotangent, explaining their definitions and how to calculate them. Following this, fundamental trigonometric identities were examined, including their proofs and the important Pythagorean identities that relate these ratios. The chapter also covered solving trigonometric equations, emphasizing methods to find angle measures that satisfy given conditions. Finally, the study extended to hyperbolic functions like sinh, cosh, cosech, tanh, and sech, describing their definitions and relevance in engineering contexts. Together, these topics provide a comprehensive understanding of trigonometric and hyperbolic functions essential for engineering mathematics.

Self-Assessment

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Written Assessment

  1. Calculate the sine, cosine, and tangent of an acute angle \( \theta = 30^\circ \) relevant to the alignment of a robotic arm in a manufacturing cell. (3 marks)

  2. A sensor on a mechatronic conveyor system is mounted at an obtuse angle of \( 120^\circ \). Calculate the cosine and sine values of this angle. (3 marks)

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Chapter Examination Questions

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SECTION A (40 Marks) - Answer ALL Questions

  1. In a Mechatronics assembly line at a Nairobi manufacturing firm, a conveyor belt is inclined at an acute angle of \(30^\circ\). Calculate the sine, cosine, and tangent of this angle. (4 marks)
  2. A robotic arm in a Kisumu electronics plant rotates through an obtuse angle of \(120^\circ\). Find the cosine of this angle. (4 marks)
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