Biomedical Engineering  ·  Level 6
Engineering Mathematics III
Chapter 1: Apply differentiation
📚 6 Topics
⚑ What you will be able to do

By the end of this chapter, you will be able to:

  • correctly determine the derivatives of various functions using the right mathematical methods
  • accurately calculate the rate of change in different situations following proper procedures
  • confidently apply differentiation techniques using standard and reliable mathematical methods

Mastering these skills will help you solve real engineering problems efficiently and make precise calculations essential in your trade.

Biomedical engineers in Kenya frequently encounter problems requiring precise rate of change analysis, such as modelling physiological signals, analysing biomedical instrumentation outputs, or optimizing drug delivery rates. Differentiation provides the mathematical tools to extract instantaneous rates and sensitivities from complex biomedical functions. Mastering differentiation techniques is essential for accurate interpretation and design in biomedical engineering applications.

1.1 Definition of derivatives of a function

Differentiation measures how a function changes as its input changes, giving the instantaneous rate of change or slope at any point. The derivative of a function \(f(x)\) at a point \(x\) is defined as the limit of the average rate of change as the interval approaches zero.

$$ f'(x) = \lim_{h \to 0} \frac{f(x+h) - f(x)}{h} $$

Worked Examples

Example 1: A biomedical signal \(f(t) = 4t^2 + 3t\) represents voltage output over time. Find the rate of change of voltage at \(t = 2\) seconds.

Given: \(f(t) = 4t^2 + 3t\), \(t = 2\) s

$$ f'(t) = \frac{d}{dt} (4t^2 + 3t) $$

$$ = 8t + 3 $$

At \(t=2\),

$$ f'(2) = 8(2) + 3 = 16 + 3 = 19 $$

Answer: 19 \text{ volts/second}

Example 2: The concentration \(C(t)\) of a drug in blood is \(C(t) = 5e^{-0.2t}\). Find the rate of change at \(t = 3\) hours.

Given: \(C(t) = 5e^{-0.2t}\), \(t=3\) h

$$ C'(t) = \frac{d}{dt} 5e^{-0.2t} = 5 \times (-0.2) e^{-0.2t} = -1 e^{-0.2t} $$

At \(t=3\),

$$ C'(3) = -1 \times e^{-0.6} = -1 \times 0.5488 = -0.5488 $$

Answer: -0.5488 \text{ mg/L per hour}

Example 3: The displacement \(s(t) = t^3 - 6t^2 + 9t\) models a biomechanical joint over time. Find the velocity at \(t=4\) seconds.

Given: \(s(t) = t^3 - 6t^2 + 9t\), \(t=4\) s

$$ s'(t) = 3t^2 - 12t + 9 $$

At \(t=4\),

$$ s'(4) = 3(16) - 12(4) + 9 = 48 - 48 + 9 = 9 $$

Answer: 9 \text{ m/s}


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🔒1.2 Differentiation from first principle

Differentiation from first principle is the fundamental definition of the derivative, which forms the basis of all differentiation techniques used in biomedical engineering analysis. In Kenya’s biomedical engineering field, understanding this concept is essent…

🔒1.3 Tables of Some Common Derivatives

In biomedical engineering, rapid differentiation of common functions is critical for modeling physiological processes such as blood flow, electrical signal propagation in nerves, and drug metabolism rates. Familiarity with standard derivatives enables engineer…

🔒1.4 Rules of differentiation

In biomedical engineering applications in Kenya, understanding and applying the rules of differentiation is critical for modelling biological systems, analysing signals, and designing medical devices. Differentiation allows engineers to determine rates of chan…

🔒1.5 Rate of change and small change

Rate of change and small change concepts are vital in biomedical engineering for analysing how physiological variables vary over time or space. These concepts help in approximating changes in signals, such as heart rate or drug concentration, over small interv…

🔒1.6 Stationary points of functions of two variables

…

Chapter Summary

This chapter introduced the concept of derivatives as a fundamental tool for understanding how functions change. Differentiation was first explored from the first principle, establishing the foundational limit definition. A selection of common derivatives was presented in tabular form to facilitate quick reference. The chapter then detailed the main rules of differentiation, including the sum and difference, product, quotient, and chain rules, each essential for handling different functional forms. Techniques for parametric and implicit differentiation expanded the application scope to more complex relationships. Finally, the chapter examined how derivatives describe the rate of change and approximate small changes in quantities, linking the theory to practical engineering contexts. Throughout, the focus remained on developing skills to differentiate functions accurately and apply these results effectively.

Self-Assessment

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Written Assessment

  1. Differentiate the function \(f(t) = 4t^3 - 5t + 7\) with respect to \(t\). (2 marks)

  2. Using first principles, find the derivative of \(f(x) = x^2\) at \(x = 3\). (3 marks)

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Chapter Examination Questions

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SECTION A (40 Marks) - Answer ALL Questions

  1. A biomedical engineer is modelling the change in blood glucose concentration \(C(t)\) over time \(t\) hours during insulin treatment. Given \(C(t) = 12e^{-0.3t}\), find \(\frac{dC}{dt}\) at \(t = 2\) hours. (4 marks)
  2. Use the first principle of differentiation to find the derivative of the function \(f(x) = 5x^2\). (4 marks)
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Am I competent?

At the start of this chapter we promised you would be able to:

  • correctly determine the derivatives of various functions using the right mathematical methods
  • accurately calculate the rate of change in different situations following proper procedures
  • confidently apply differentiation techniques using standard and reliable mathematical methods

Tick each one you can genuinely do.

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