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Biomedical engineers frequently encounter hyperbolic functions when analyzing physiological processes such as nerve signal transmission, blood flow dynamics, and modeling of biological tissues. These functions, which resemble trigonometric functions but relate to hyperbolas instead of circles, are fundamental in solving differential equations describing biomedical systems. Mastery of hyperbolic functions enables engineers to model, simulate, and interpret complex biological phenomena accurately within Kenya’s healthcare and research institutions.
Hyperbolic functions extend the concept of exponential functions and are intrinsic in biomedical engineering for describing phenomena such as membrane potentials and blood vessel elasticity. This section introduces the fundamental hyperbolic functions, their definitions based on exponential expressions, and their graphical behavior, which aids in interpreting biomedical data and signals.
Hyperbolic functions are defined using exponential functions. The primary hyperbolic functions are hyperbolic sine (\(\sinh x\)), hyperbolic cosine (\(\cosh x\)), and hyperbolic tangent (\(\tanh x\)). Their reciprocals are hyperbolic cosecant (\(\csch x\)), hyperbolic secant (\(\sech x\)), and hyperbolic cotangent (\(\coth x\)).
$$\sinh x = \frac{e^x - e^{-x}}{2}$$
$$\cosh x = \frac{e^x + e^{-x}}{2}$$
$$\tanh x = \frac{\sinh x}{\cosh x} = \frac{e^x - e^{-x}}{e^x + e^{-x}}$$
$$\csch x = \frac{1}{\sinh x} = \frac{2}{e^x - e^{-x}}$$
$$\sech x = \frac{1}{\cosh x} = \frac{2}{e^x + e^{-x}}$$
$$\coth x = \frac{1}{\tanh x} = \frac{e^x + e^{-x}}{e^x - e^{-x}}$$
Example 1: Calculate \(\sinh 1\) for modeling the voltage response in a nerve fiber.
Given: \(x = 1\)
$$\sinh 1 = \frac{e^1 - e^{-1}}{2}$$
$$= \frac{2.7183 - 0.3679}{2}$$
$$= \frac{2.3504}{2}$$
Answer: 1.1752
Example 2: Find \(\cosh 0.5\) relevant to modeling blood vessel elasticity.
Given: \(x = 0.5\)
$$\cosh 0.5 = \frac{e^{0.5} + e^{-0.5}}{2}$$
$$= \frac{1.6487 + 0.6065}{2}$$
$$= \frac{2.2552}{2}$$
Answer: 1.1276
Example 3: Determine \(\tanh 2\) used in simulating insulin diffusion in tissues.
Given: \(x = 2\)
$$\tanh 2 = \frac{e^2 - e^{-2}}{e^2 + e^{-2}}$$
$$= \frac{7.3891 - 0.1353}{7.3891 + 0.1353}$$
$$= \frac{7.2538}{7.5244}$$
Answer: 0.9640
Example 4: Calculate \(\sech 1\) for analyzing the decay of a biological signal.
Given: \(x = 1\)
$$\sech 1 = \frac{2}{e^1 + e^{-1}}$$
$$= \frac{2}{2.7183 + 0.3679}$$
$$= \frac{2}{3.0862}$$
Answer: 0.6470
Example 5: Evaluate \(\coth 0.8\) in modeling blood pressure waveforms.
Given: \(x = 0.8\)
$$\coth 0.8 = \frac{e^{0.8} + e^{-0.8}}{e^{0.8} - e^{-0.8}}$$
$$= \frac{2.2255 + 0.4493}{2.2255 - 0.4493}$$
$$= \frac{2.6748}{1.7762}$$
Answer: 1.5058
Graphical understanding of hyperbolic functions reveals their behavior patterns essential for biomedical signal analysis. The hyperbolic sine is an odd function, symmetric about the origin, while hyperbolic cosine is even, symmetric about the y-axis. Their growth rates and asymptotic behavior assist in interpreting physiological responses.
$$\sinh (-x) = -\sinh x$$
$$\cosh (-x) = \cosh x$$
$$\tanh (-x) = -\tanh x$$
Example 1: Determine the value of \(\sinh (-1)\) using the odd function property.
Given: \(x = -1\)
$$\sinh (-1) = -\sinh 1$$
From previous calculation, \(\sinh 1 = 1.1752\)
$$\sinh (-1) = -1.1752$$
Answer: -1.1752
Example 2: Verify the even property of \(\cosh x\) by calculating \(\cosh (-0.7)\).
Given: \(x = -0.7\)
$$\cosh (-0.7) = \cosh 0.7 = \frac{e^{0.7} + e^{-0.7}}{2}$$
$$= \frac{2.0138 + 0.4966}{2}$$
$$= \frac{2.5104}{2}$$
Answer: 1.2552
Example 3: Evaluate \(\tanh (-1.5)\) demonstrating the odd function property.
Given: \(x = -1.5\)
$$\tanh (-1.5) = -\tanh 1.5$$
Calculate \(\tanh 1.5\):
$$\tanh 1.5 = \frac{e^{1.5} - e^{-1.5}}{e^{1.5} + e^{-1.5}} = \frac{4.4817 - 0.2231}{4.4817 + 0.2231} = \frac{4.2586}{4.7048} = 0.9051$$
$$\tanh (-1.5) = -0.9051$$
Answer: -0.9051
Example 4: Find the limit of \(\tanh x\) as \(x \to \infty\), relevant for saturation behavior in biomedical sensors.
$$\lim_{x \to \infty} \tanh x = \lim_{x \to \infty} \frac{e^x - e^{-x}}{e^x + e^{-x}}$$
For very large \(x\), \(e^{-x} \approx 0\), so
$$= \frac{e^x}{e^x} = 1$$
Answer: 1
Example 5: Sketch the graph of \(\cosh x\) for \(x\) in \([-2,2]\) and identify its minimum value.
At \(x = 0\):
$$\cosh 0 = \frac{e^0 + e^0}{2} = \frac{1 + 1}{2} = 1$$
Since \(\cosh x \geq 1\) for all real \(x\), the minimum value is 1 at \(x=0\).
Answer: Minimum value of 1 at \(x=0\)
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Create a free accountThis chapter introduced the fundamental hyperbolic functions including hyperbolic sine, cosine, tangent, and their reciprocal functions, alongside their definitions and characteristic graphs. It explored the important properties of these functions, emphasizing their distinct behavior compared to trigonometric functions. The chapter then presented key hyperbolic identities, such as fundamental and Pythagorean-like identities, as well as sum and difference formulas, double-angle, and half-angle formulas, which are essential for manipulating expressions involving hyperbolic functions. Methods for solving basic hyperbolic equations were covered, including techniques to simplify and solve more complex equations using these identities. The concept of inverse hyperbolic functions was introduced with their definitions and properties, followed by strategies for solving equations that involve these inverse functions. Finally, the chapter highlighted practical applications of hyperbolic functions in engineering contexts, demonstrating their relevance in solving real-world problems.
Calculate the value of \(\sinh 0.5\) using the definition \(\sinh x = \frac{e^x - e^{-x}}{2}\). (2 marks)
Find \(\cosh 1.2\) given \(\cosh x = \frac{e^x + e^{-x}}{2}\). (2 marks)
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