Cooperative Management  ·  Level 5
Business Mathematics And Statistics
Chapter 3: Apply statistical matrices
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Compiled by: Susan Mburu

Matrices are essential mathematical tools in cooperative management for organizing and analyzing data related to member contributions, loan portfolios, and financial records. They provide a structured way to handle multiple data points simultaneously, facilitating decision-making and reporting. This chapter introduces matrices and their operations, focusing on practical applications in cooperatives and related business environments in Kenya.

3.1 Introduction to matrices

Matrices are rectangular arrays of numbers arranged in rows and columns, used to represent data compactly. In cooperative management, matrices can represent financial transactions, member data, or resource allocation efficiently. The size of a matrix is given by the number of rows and columns, and each element is identified by its position.

$$A = \begin{bmatrix} a_{11} & a_{12} & \cdots & a_{1n} \\ a_{21} & a_{22} & \cdots & a_{2n} \\ \vdots & \vdots & \ddots & \vdots \\ a_{m1} & a_{m2} & \cdots & a_{mn} \end{bmatrix}$$

Worked Examples

Example 1: A cooperative records the monthly savings of 3 members over 2 months as matrix \(A\):

Given:
\[ A = \begin{bmatrix} 5000 & 6000 \\ 4500 & 7000 \\ 5500 & 6500 \end{bmatrix} \]

This is a \(3 \times 2\) matrix representing 3 members (rows) and 2 months (columns).
Answer: The matrix has 3 rows and 2 columns.

Example 2: Identify the element in the 2nd row and 1st column of matrix \(A\).

Given:
\[ A = \begin{bmatrix} 5000 & 6000 \\ 4500 & 7000 \\ 5500 & 6500 \end{bmatrix} \]

Element \(a_{21} = 4500\)
Answer: \(4500\)

Example 3: Construct matrix \(B\) representing loan amounts for 2 loan types across 4 branches:

$$B = \begin{bmatrix} 120000 & 150000 \\ 100000 & 130000 \\ 90000 & 110000 \\ 115000 & 140000 \end{bmatrix}$$

\(B\) is a \(4 \times 2\) matrix (4 branches, 2 loan types).
Answer: Matrix \(B\) with dimensions \(4 \times 2\).

Example 4: Determine if matrix \(C\) is square:

$$C = \begin{bmatrix} 1 & 2 & 3 \\ 4 & 5 & 6 \\ 7 & 8 & 9 \end{bmatrix}$$

\(C\) has 3 rows and 3 columns, so it is square.
Answer: \(C\) is a square matrix of order 3.

Example 5: Given matrix \(D\) with 2 rows and 3 columns, write its general form.

$$D = \begin{bmatrix} d_{11} & d_{12} & d_{13} \\ d_{21} & d_{22} & d_{23} \end{bmatrix}$$

Answer: \(D\) is a \(2 \times 3\) matrix with elements \(d_{ij}\).

Practice Questions

  1. A cooperative has 5 members and records their weekly contributions for 3 weeks in matrix \(M\). If the first member contributed Ksh 2000, 2500, and 3000 in weeks 1, 2, and 3 respectively, write the first row of matrix \(M\). (3 marks)

  2. Given matrix \(P = \begin{bmatrix} 100 & 200 \\ 150 & 250 \\ 120 & 180 \end{bmatrix}\), identify the element in the 3rd row and 2nd column. (2 marks)

  3. Construct a \(2 \times 2\) matrix representing the sales of two products in two branches, with values: Branch 1 sells 500 and 600 units; Branch 2 sells 700 and 800 units. (4 marks)

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🔒3.2 Operations of matrices

Matrix operations allow manipulation of data arrays for analysis and computation in cooperative management tasks such as budgeting, loan tracking, and member statistics. The primary operations include addition, subtraction, multiplication, and a special treatm…

🔒3.3 Solving a 2×2 matrix

Solving a 2×2 matrix is a fundamental skill in cooperative management, especially when dealing with systems of linear equations such as budgeting constraints or resource allocation problems. In Kenya’s cooperative sector, managers often use these techniques to…

🔒3.4 Determinants of a 2×2 matrix

Determinants are scalar values used to determine the invertibility of matrices and play a critical role in solving linear systems. In cooperative management, determinants help verify if financial models or resource allocations have unique solutions or if adjus…

🔒3.5 Inverse of a 2×2 Matrix

The inverse of a 2×2 matrix is a fundamental tool in cooperative management for solving systems of linear equations related to financial records, membership data, and resource allocation. Understanding how to compute the inverse allows managers in Kenyan coope…

🔒3.6 Application of Matrices in Solving Business Operations

Matrices provide cooperative managers in Kenya with powerful methods to analyze, plan, and optimize business operations such as resource allocation, financial forecasting, and membership data management. By representing complex systems as matrices, operations…

Chapter Summary

This chapter introduced the concept of matrices as an essential tool in business mathematics and statistics, focusing on their structure and use. It covered the fundamental operations of matrices including addition, subtraction, division, and multiplication, explaining how these operations are performed and their significance. The chapter then detailed methods for solving a 2 by 2 matrix, providing a foundation for more complex applications. The concept of determinants for a 2 by 2 matrix was explained, highlighting its role in matrix operations and solutions. Following this, the process of finding the inverse of a 2 by 2 matrix was discussed, emphasizing its importance in solving linear systems. Finally, the chapter demonstrated how matrices can be applied to solve various business operations problems, showcasing their practical value in real-world decision making and analysis.

Self-Assessment

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Written Assessment

  1. Given two matrices representing monthly savings (in Ksh 1,000) of two cooperative groups over two months:
    \[ A = \begin{bmatrix} 15 & 20 \\ 18 & 22 \end{bmatrix}, \quad B = \begin{bmatrix} 5 & 8 \\ 7 & 10 \end{bmatrix} \]
    Calculate the matrix \(C = A + B\).

  2. The cooperative’s expenditure matrix for two departments over two quarters is:
    \[ X = \begin{bmatrix} 50 & 40 \\ 30 & 20 \end{bmatrix} \]
    and the revenue matrix for the same departments and quarters is:
    \[ Y = \begin{bmatrix} 70 & 65 \\ 45 & 35 \end{bmatrix} \]
    Find the profit matrix \(P = Y - X\).

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Chapter Examination Questions

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SECTION A (40 Marks) - Answer ALL Questions

  1. Given matrices \(A = \begin{bmatrix} 5 & 3 \\ 2 & 4 \end{bmatrix}\) and \(B = \begin{bmatrix} 1 & 6 \\ 7 & 2 \end{bmatrix}\), find the matrix \(A + B\). (4 marks)
  2. For matrices \(C = \begin{bmatrix} 8 & 2 \\ 5 & 9 \end{bmatrix}\) and \(D = \begin{bmatrix} 3 & 1 \\ 4 & 7 \end{bmatrix}\), calculate \(C - D\). (4 marks)
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